LED » Historie » Version 3
Maximilian Seesslen, 06.09.2023 13:06
| 1 | 1 | Maximilian Seesslen | h1. LED |
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| 2 | |||
| 3 | |||
| 4 | Vforward = 2V |
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| 5 | Iforward = 20mA = 0,020A |
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| 6 | |||
| 7 | R=2/0,02=100Ohm |
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| 8 | U2=I*R2=100*0,02=2V |
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| 9 | |||
| 10 | 3 | Maximilian Seesslen | h2. Berechnung Vorwiederstand |
| 11 | |||
| 12 | 1 | Maximilian Seesslen | I= U/(R1+R2) |
| 13 | R1+R2=U/I |
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| 14 | R1 = (U / I ) - R2 = (3/0,02)-100 = 50 |
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| 15 | 3 | Maximilian Seesslen | |
| 16 | *Rvor = ( V -Vf ) / If* |
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| 17 | 1 | Maximilian Seesslen | |
| 18 | R=50+100=150 |
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| 19 | I=3/150=20mA |
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| 20 | |||
| 21 | Just double it: |
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| 22 | R=100+100 |
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| 23 | I = 3/200 = 0,015 |
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| 24 | |||
| 25 | Just tribble it: |
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| 26 | I = 3/250 = 0,012 |
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| 27 | |||
| 28 | Just 4 times: |
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| 29 | I = 3/300 = 0,010 |
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| 30 | |||
| 31 | 2 | Maximilian Seesslen | R1= ( Ug / If ) - ( Uf / If ) = (Ug-Uf)/If |
| 32 | 1 | Maximilian Seesslen | |
| 33 | U |
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| 34 | --- |
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| 35 | R*I |
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| 36 | |||
| 37 | R1 R2 |
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| 38 | -- = -- |
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| 39 | U1 U2 |